TCS
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by*
SkillRack
on
16-Mar-2016 11:35

x,y,z are positive integers. If x(y+z)=63, y(z+x)=40, z(y+x)=33, what is the value of x+y+z?

RAJAT SHARMA
on
17-Mar-2016 17:17

14

PRITHIVIRAJ G
on
21-Mar-2016 11:57

12

Varun D Suvarna
on
28-Mar-2016 15:21Accepted Solution

As we look at the third equations,
z = 11 or 3
but, z=11 does not satisfies the other two equations
therefore, z=3
=> y = 11-x
Now, as we see in the second equation, i.e.,
y(z+x)=40
=> (11-x)(3+x)=40
=> x=1; y=10
Therefore, x+y+z = 14