TCS
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SkillRack
on
16-Mar-2016 11:35

When the sum of the numbers from 9 to 33 is divided by 9 the remainder is

ACHAL MEHTA
on
16-Mar-2016 19:32

7

RAJAT SHARMA
on
17-Mar-2016 17:12

3

ANKIT KUMAR CHANDRAKER
on
18-Mar-2016 17:23

3

VETURI SAMEER
on
20-Mar-2016 13:13

Sn=1/2*n(2a+(n-1)d)
472/9=3

PRITHIVIRAJ G
on
21-Mar-2016 11:53

6

NEERAJ SINGH
on
21-Mar-2016 14:01

Sm=n/2(2a+(n-1)d) where n=24, a=9,d=1 thn sm=492 492/9=6remndr

DARSHAN DAYAL SURI
on
28-Mar-2016 15:25Accepted Solution

Sm=(33*34)/2-(8*9)/2=525
525/9=58+(3/9) where 3 is the remainder

VINAYAK A MODI
on
29-Mar-2016 17:42

number of terms=25(i.e 33-9=24 as both tems are involved total terms=24+1=25)
sum=25/2[2*9+24*1]=525
remainder=525/9=3

DASARI JAGADEESH
on
25-Apr-2016 12:22

7