A square is of side 1 km. A man travels first two sides with the 30 miles/hour and third side with 60 km/h. What is the speed at which the man has to travel the fourth side, if the overall average speed is 60 kmph?

on
8-Apr-2014 18:48

ans : 120

ans : 120

on
16-Jul-2014 01:04

90

90

on
17-Jul-2014 21:41

84<div><br></div>

84<div><br></div>

on
4-Aug-2014 18:18

84 kmph or 52.5 mph

84 kmph or 52.5 mph

on
12-Aug-2014 21:45

84

84

on
23-Aug-2014 20:24

60 km/hr

60 km/hr

on
27-Aug-2014 20:58

pls explain?

pls explain?

on
28-Aug-2014 15:26

sam<br>please explain?<br>if you know.<br>

sam<br>please explain?<br>if you know.<br>

on
9-Sep-2014 10:10

<div><span style="font-family: Arial, Verdana; font-size: 13px; font-weight: bold;">pls gve answer</span></div>

<div><span style="font-family: Arial, Verdana; font-size: 13px; font-weight: bold;">pls gve answer</span></div>

on
9-Sep-2014 11:50

which one is the correct answer<br><br>

which one is the correct answer<br><br>

on
14-Sep-2014 11:15

<span style="font-weight: bold;">pls explain priishree</span><div><span style="font-weight: bold;"><br></span></div>

<span style="font-weight: bold;">pls explain priishree</span><div><span style="font-weight: bold;"><br></span></div>

on
17-Sep-2015 07:34

<div>120 average speed= total distance/total time</div><div>speed of covering 1st two sides=30miles/h ; 1mile=1.60km so 30*1.60=48km/h</div><div>total distance= 4km(4 sides)</div><div>total time =z=1/48+1/48+1/60+1/x where x is speed of the 4th side</div><div>Now, 60=4/z </div><div>by solving it x comes out 120km/h </div>

<div>120 average speed= total distance/total time</div><div>speed of covering 1st two sides=30miles/h ; 1mile=1.60km so 30*1.60=48km/h</div><div>total distance= 4km(4 sides)</div><div>total time =z=1/48+1/48+1/60+1/x where x is speed of the 4th side</div><div>Now, 60=4/z </div><div>by solving it x comes out 120km/h </div>

on
1-Oct-2015 10:33

120

120

on
11-Oct-2015 21:26

84kmph or 52.5 mph

84kmph or 52.5 mph

on
28-Oct-2015 12:46

120

120

on
19-Jan-2016 23:04

120

120

on
29-Jan-2016 16:10

120

120

on
1-Feb-2016 14:32

120

120

on
9-Feb-2016 14:19

84...

84...

on
25-Feb-2016 00:16

120, (60*4)=240; but 30+30+60=120; so another 120 is needed to make 240. and for avg. 60 km speed

120, (60*4)=240; but 30+30+60=120; so another 120 is needed to make 240. and for avg. 60 km speed

on
28-Feb-2016 21:35

120

120

on
1-Mar-2016 13:24

120 as the time taken will also var with the speed 30 miles/h =48 km time taken for 1st side=1/48 for second side 1/48 for 3rd side1/60 for fourth side 1/x and then we know 60=4/s where s is the average time s=1/48+1/48+1/60+1/x on solving x=120

120 as the time taken will also var with the speed 30 miles/h =48 km time taken for 1st side=1/48 for second side 1/48 for 3rd side1/60 for fourth side 1/x and then we know 60=4/s where s is the average time s=1/48+1/48+1/60+1/x on solving x=120

on
12-Mar-2016 11:36

120

120

on
14-Mar-2016 21:03

120

120

on
16-Mar-2016 19:17

120, (60*4)=240; but 30+30+60=120; so another 120 is needed to make 240

120, (60*4)=240; but 30+30+60=120; so another 120 is needed to make 240

on
29-Mar-2016 10:49

120

120

on
12-Apr-2016 10:03

120

120

on
12-Apr-2016 11:29

Approx 55.38kmph

Approx 55.38kmph

on
18-Apr-2016 11:28

83.6 km/hr

83.6 km/hr

on
5-Jun-2016 13:06

120

120

on
5-Jun-2016 13:06

120

120

on
8-Jun-2016 08:13

120

120

on
2-Jul-2016 11:46

120

120

on
20-Jul-2016 18:29

120

120

on
25-Jul-2016 18:39

120

120

on
26-Jul-2016 18:33

120

120

on
1-Aug-2016 15:23

120

120

on
23-Aug-2016 21:36

120

120

on
7-Sep-2016 12:14

83.4394 km/hr

83.4394 km/hr

on
7-Sep-2016 23:11

Basically 1mile=1.6093km In first two side it maintain 30 mile per hour which is 48.2803 kmph In 3rd side it take 60kmph If 48.2803+48.2803+60+X =240(Basically total derived from average of 60kmph) We get x=83.4394 THEREFORE THE FOURTH SIDE SPEED IS 83.4394KMPH

Basically 1mile=1.6093km In first two side it maintain 30 mile per hour which is 48.2803 kmph In 3rd side it take 60kmph If 48.2803+48.2803+60+X =240(Basically total derived from average of 60kmph) We get x=83.4394 THEREFORE THE FOURTH SIDE SPEED IS 83.4394KMPH

on
19-Oct-2016 16:29

84km/hr

84km/hr

on
5-Jan-2017 10:38

120

120

on
6-Feb-2017 20:14

65.86

65.86

on
22-Feb-2017 17:00

84

84

on
1-Mar-2017 14:59

120miles/hr let the sides be , a,b,c,d speed along a=30miles/hr along b=30miles/hr along c=60miles/hr along d=z miles/hr given: avg=60miles/hr=(30+30+60+z)/4 on solving; z=120 miles/hr

120miles/hr let the sides be , a,b,c,d speed along a=30miles/hr along b=30miles/hr along c=60miles/hr along d=z miles/hr given: avg=60miles/hr=(30+30+60+z)/4 on solving; z=120 miles/hr

on
14-Mar-2017 11:33

120

120

on
24-Jul-2017 15:16

1 mile =1.60934km 30 miles/hour = 48.2802 km/h. given:average = 60km/h Let x be the fourth side. 60 = (x+48.2802 +48.2802+60)/4 x=83.4396 km/h is the speed at which the man has to travel the fourth side

1 mile =1.60934km 30 miles/hour = 48.2802 km/h. given:average = 60km/h Let x be the fourth side. 60 = (x+48.2802 +48.2802+60)/4 x=83.4396 km/h is the speed at which the man has to travel the fourth side