#include using namespace std; int main() { // your code goes here int a=5; cout<<(++a + ++a + ++a) ; return 0; }


Solution Required
Abinesh
0 5 258
12 months ago

#include <iostream>
using namespace std;

int main() {
	// your code goes here
	int a=5;
	cout<<(++a + ++a + ++a) ;
	return 0;
}

aravind G
0 4 361
12 months ago

22 is the answer when the evaluation is from right to left so values will be 8 + 7 +6 when 6+7 is added it turns as 7+7 and 14 is returned when 14 is added with 8 22 is printed
NARESH BABU G
18 12 1589
12 months ago

All this confusion arises because of operator + + is more like a function which accepts arguments i.e: a+b --> +(a,b) so ++a + ++a --> +(++a,++a) //both are same after compilation: ++a + ++a + ++a =22 ++a +(++a + ++a)=24 (++a + ++a)+ ++a=22 This is all because the function accepts final value only: x=5 add(++x,++x); //it should pass as add(6,7) but it passes as: add(7,7) //becauz only after calculation of x is the value passed. thus ++a + ++a + ++a (7+7)+ ++a 14 + 8 = 22

NARESH BABU G
18 12 1589
12 months ago

Last reply is the answer Here are examples to better understand: Not in the same comment since there is a limit of 500 characters cout and calculation are performed in left to right order and fuction arguments from right to left order (above are found from experimentation of online compiler) More example reason for experimental conclusion are attached with the picture.

R ANUSHA
0 0 125
12 months ago

Here the operation begins from right towards left. so at first ++a= 6; then ++a + ++a=7+6 but instead it takes the calculated value of' a' so it becomes 7+7 and then now value of 'a' is 7. then (1+7) +14=8+14. thus the output would be 22
VISHAL PERIYASAMY R
2 11 1334
12 months ago

21
DHIVYA S
0 0 255
12 months ago

27
Hemakaviya. S
0 0 112
12 months ago

a=5 (++a + ++a) + ++a//(6,7) (7,7)+ ++a 14+8= 22 operators right to left
PRAVEEN KUMAR. S
0 1 319
11 months ago

this is the ans

KALAIVANI G
0 0 84
8 months ago

24
BAVIREDDY VENKATA MANISH BABU
0 0 113
5 months ago

22